If you wish to prepare 2.00 g of BaSO4 (233.43 g/mol)

Question
If you wish to prepare 2.00 g of BaSO4 (233.43 g/mol)from 1.5 M Na2SO4 (142.04 g/mol) and 1.0 M BaCl2(208.23 g/mol) how many milliliters (mL) of 1.0 M BaCl2 will you need assuming 100% of the BaCl2 reacts and precipitates to give the desires BaSO4?

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